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it is given that ∫e -ax ^2 dx = (pi/a)^0.5. The value ∫x 2 e -ax^2 dx is given by

it is given that ∫e-ax^2dx = (pi/a)^0.5. The value ∫x2e-ax^2dx is given by

Grade:12th pass

1 Answers

Vikas TU
14149 Points
4 years ago
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