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Grade: 11

                        

It is concluded from measurements of the red shift of the emitted light that quasar Q 1 is moving away from us at a speed of 0.788c. Quasar Q 2 , which lies in the same direction in space but is closer to us, is moving away from us at speed 0.413c. What velocity for Q 2 would be measured by an observer on Q 1 ?

5 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
							To obtain the velocity of Q2, substitute 0.788c for v0, -0.413c for u in the equation v = (v0 + u) / (1 + v0u/c2),
v = (v0 + u) / (1 + v0u/c2)
= (0.788c + (-0.413c)) / (1+((0.788c) (-0.413c))/c2)
= 0.375c / (1-0.3254)
= 0.556c
From the above observation we conclude that, the velocity of Q2 measured by an observer on Q1 would be 0.556c.
5 years ago
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