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Grade: 11
        
It is concluded from measurements of the red shift of the emitted light that quasar Q1 is moving away from us at a speed of 0.788c. Quasar Q2, which lies in the same direction in space but is closer to us, is moving away from us at speed 0.413c. What velocity for Q2 would be measured by an observer on Q1 ?
4 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
							To obtain the velocity of Q2, substitute 0.788c for v0, -0.413c for u in the equation v = (v0 + u) / (1 + v0u/c2),
v = (v0 + u) / (1 + v0u/c2)
= (0.788c + (-0.413c)) / (1+((0.788c) (-0.413c))/c2)
= 0.375c / (1-0.3254)
= 0.556c
From the above observation we conclude that, the velocity of Q2 measured by an observer on Q1 would be 0.556c.
4 years ago
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