Is there a specific way to determine the function of a given graph?if not, Then how will we solve the following question? the accelaration – time graph of a particle is such that at t=0, a= -2, and at t=1, a=0. (I cant draw the graph so i am giving data deducable form graph) (i) Find an expression of velocity in terms of t and draw v-t (ii) Derive x9t) and hence calculate the displacement of the particle in the time interval from t=2 sec to t=4 sec Assume that x=0,v=0 at t=0 ???? please help

Question

Arun Kumar · Answer

No not by the information you have given. But try integrating the graph by intervals rather than taking initial to final. Arun Kumar IIT Delhi Askiitians Faculty

Arun Kumar · Answer

Now i have seen the attached image by you it wasn't coming before.
So,
from the graph we can say
a=2t-2;
$a=dv/dt=2t-2\\=>dv=(2t-2)dt \\=>v=t^2-2t+c$
Its quadratic equation you can draw its graph.
By the conditons given t=0 v=0 => c=0
$=>v=t^2-2t \\=>dx/dt=v=t^2-2t \\=>x=t^3/3-t^2+c$
again t=0 x=0; =>c=0
$\\=>x=t^3/3-t^2$
Rest you can do.
Arun Kumar
IIT Delhi
Askiitians Faculty

Palash Agarwal · Answer

Arun sir i was asking basically about the first step, that how do we find that expression 2t-2 Rest i know

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