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# `Is there a specific way to determine the function of a given graph?if not, `` `Then how will we solve the following question?the accelaration – time graph of a particle is such that at t=0, a= -2, and at t=1, a=0. (I cant draw the graph so i am giving data deducable form graph)(i) Find an expression of velocity in terms of t and draw v-t(ii) Derive x9t) and hence calculate the displacement of the particle in the time interval from t=2 sec to t=4 secAssume that x=0,v=0 at t=0 ????please help

Arun Kumar IIT Delhi
7 years ago
No not by the information you have given.
But try integrating the graph by intervals rather than taking initial to final.
Arun Kumar
IIT Delhi
Arun Kumar IIT Delhi
7 years ago
Now i have seen the attached image by you it wasn't coming before.
So,
from the graph we can say
a=2t-2;
$a=dv/dt=2t-2\\=>dv=(2t-2)dt \\=>v=t^2-2t+c$
Its quadratic equation you can draw its graph.
By the conditons given t=0 v=0 => c=0
$=>v=t^2-2t \\=>dx/dt=v=t^2-2t \\=>x=t^3/3-t^2+c$
again t=0 x=0; =>c=0
$\\=>x=t^3/3-t^2$
Rest you can do.
Arun Kumar
IIT Delhi