badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

Initial velocity of a particle moving in xy plane is given as vector u equal to two Icap + 3 jcap metre per second if acceleration of a particle is two icap + 2 J cap metre per second square find first position second velocity III displacement at t=10second at ( t=0,x=2, y=0)

2 years ago

Answers : (1)

Saurav
224 Points
							
First solve for I cap as single direction and then for j cap separately
They don't affect each other
Just use these equations
S=ut +half a t square
V=u+at
Displacement by final co-ordinate to initial coordinate distance
Hope this helped u 
Please qpprobaif it helps u:)
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details