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`        In this question(see attachment) car is moving above hill.So,why for calculating work done we use mv2/2-mgh as it was moving above the hill?Please explain this question to me.`
one year ago

```							Here given in the question :-Car Mass m = 1400 kg .h = 10 mMoving at Initial speed v= 54 km/h = (54000/3600) m/s = 15 m/sec.Now Initial Kinetic Energy of the car ,= 1/2 mv²= 1/2 (1400 x 15²)= 315000/2= 157500 J.Here final velocity and Final Kinetic energy both are Zero.Now change in Kinetic Energy = Final - Initial= 0 - 157500= -157500 J.So change in Kinetic energy is also equal to W.D by all force.Thus work done by gravity,= mgh= 1400 x 9.8 (-10)= 1400 x -98= -137200 .Here, change in Kinetic energy = Work done by the friction + Work done by the gravity.-157500 = Work done by friction + (- 137200)Work done by the friction = -157500 +137200 =  -20,300Hence, the work done against the friction =  20300 J
```
one year ago
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