In the shown arrangement mass of A = 1 kg, mass of B = 2 kg. Coefficient of friction between A and B = 0.2. There is no friction between B and ground. The frictional force on A is

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Arun · Answer

Dear student Normal reaction force acting on A = 1 * g = g Newton Hence frictional force as shown in figure = mu * N = 2 * 9.8 = 19.6 Newton

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In the shown arrangement mass of A = 1 kg, mass of B = 2 kg. Coefficient of friction between A and B = 0.2. There is no friction between B and ground. The frictional force on A is

In the shown arrangement mass of A = 1 kg, mass of B = 2 kg. Coefficient of friction between A and B = 0.2. There is no friction between B and ground. The frictional force on A is

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In the shown arrangement mass of A = 1 kg, mass of B = 2 kg. Coefficient of friction between A and B = 0.2. There is no friction between B and ground. The frictional force on A is

In the shown arrangement mass of A = 1 kg, mass of B = 2 kg. Coefficient of friction between A and B = 0.2. There is no friction between B and ground. The frictional force on A is

1 Answers

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