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In the figure shown acceleration of monkey relative to rope if it exerts a force of 80N on string will be?
If monkey move up then 5kg block will come down with f2=50N So for monkey : 10a(mass of monkey *acc)-T=(f/15)*10 ........ eqn-(1) Then for next block : 2T-100=(f/15)*5 By sub t=80 in eqn 3 which is obtained by eliminating 'f' which is Eqn: a=(3T-100)/10;
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