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Grade 12th passMechanics

In the figure at the free end of the light string, a force F is applied to keep the suspended mass of 18 kg at rest. Assuming pulley is light then the force exerted by the ceiling on the system is (1) 200N(2) 120N(3) 180N(4) 240N

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Profile image of Vikash Kumar Singh
8 Years agoGrade 12th pass
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1 Answer

Profile image of Pankaj Kumar
8 Years ago
3T=180
or, T= 60N
Now, F=T=60N
Therefore, total force on ceiling is, 4T=240N. (Option 4)
(I cannot attach an solution image here, there seems no option for doing it in the answers.)