In the diagram, the tension at the rigid support is (g = 10 m/s)

T1=600+130 T3=400+40T2=420 because second man moving downward with velocity Add T1+T2+T3= 1580NOne man moving upward with acc 2 and another man moving downward acc 1

For 40 kg400 – T1 = 40 (1)T1 = 360 Nfor 50 kg500 + T1 – T2 = 50 (2) T2 = 760 Nfor 60 kg T3 – 600 – T2 = 60 (2)T3 = 1580 NT3 will be the tension at the topmost point on the rigid suppor