Grade 11Mechanics
In the arrangement shown the rod is hinged at A and the system is in equilibrium then the mass of rod is (m=5kg)
1 Answer
Vikas TU
First do the torque about the hinged and equate it to zero as net moment about the hinged part should be zero.
Hence,the equation becomes:
Mgl/2 = T x l
T = Mg/2................(1)
and
for m mass,
mg – T = ma
as the system is in equilibrium the a =0
Therfore,
T = mg...............(2)
From both the eqns. we get,
Mg/2 = mg
M =2m => 2*5 = 10 kg.
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