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In the ammonia (NH 3 ) molecule, the three hydrogen (H) atoms form an equilateral triangle, the distance between centers of the atoms being 16.28 X 10 -11 m, so that the center of the triangle is 9.40 X 10 -11 m from each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, the three hydrogen constituting the base(see Fig.)The nitrogen/hydrogen distance is 10.14 X 10 -11 m and the nitrogen/hydrogen atomic mass ratio is 13.9. Locate the center of mass relative to the nitrogen atom.

In the ammonia (NH3) molecule, the three hydrogen (H) atoms form an equilateral triangle, the distance between centers of the atoms being 16.28 X 10-11 m, so that the center of the triangle is 9.40 X 10-11 m from each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, the three hydrogen constituting the base(see Fig.)The nitrogen/hydrogen distance is 10.14 X 10-11 m and the nitrogen/hydrogen atomic mass ratio is 13.9. Locate the center of mass relative to the nitrogen atom.

Grade:upto college level

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
6 years ago
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