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In one of his many action movies Jackie Chan jumped off a building by wrapping a rope around his waist and then allowed it to unwind as he fell to the ground, much the same as a yo-yo Assuming his acceleration toward was a constant much less than g, the tension in the rope would be (A) almost equal to his weight. (B) Exactly equal to his weight, (C) Much less than his weight, (D) Exactly zero. (See Who Am I starring Jackie Chan.)

5 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
							The correct option is: .(A) almost equal to his weight
When the Jackie Chan of acceleration, fell to the ground, he possesses two kinds one is the angular acceleration and the other is the linear acceleration. The angular acceleration is provided by the tension in the string and the frictional force between the rope and the Jackie Chan. Linear acceleration, on the other hand, result from the difference between the weight of Jackie Chan and the tension in the rope.
If the tension in the rope is comparable to the weight of Jackie Chan, the downward linear acceleration would be smaller in comparison to acceleration due to gravity. Therefore if the tension in the rope is comparable to the weight of Jackie Chan, only then the acceleration of Jackie Chan would be much lesser than g.
Hence (A) is the correct option and the rest are ruled out.
5 years ago
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