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In fig shown block B moves down with a velocity 10m/s.The velocity of A in the position shown is

In fig shown block B moves down with a velocity 10m/s.The velocity of A in the position shown is

Question Image
Grade:11

2 Answers

Samuel Garry
61 Points
3 years ago
Its answer is 12.5 m/sec till body A will remain at surface 
The ideal weight of a tempting the sets of question is breaking the component of velocity in the direction of string and then equating it equal to velocity of body B
Net velocity of body A be v
Take its component in the direction of string as v cos 37
So 10 = 4/5 v
V = 12.5
 
Avi
13 Points
2 years ago
If velocity of A is V then velocity of B is 2V
Velocity of A= 2× velocity of B
V cos37° = 2×10
V×4÷5 = 20
V = 20×5÷4
V=25m/s

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