In case of pure rolling of a disc,a=฿r,where ฿is angular acceleration.a=ฯ/I×ra=f.r/0.5mr^2×ra=2f/m.buta=Fnet/m so a=f/m.which one is correct and why?I have attached a picture of my dpubt also.

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Gaurav Gupta · Answer

as the plank is free to move there will be some acceleration of plank.

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In case of pure rolling of a disc,a=฿r,where ฿is angular acceleration.a=ฯ/I×ra=f.r/0.5mr^2×ra=2f/m.buta=Fnet/m so a=f/m.which one is correct and why?I have attached a picture of my dpubt also.

In case of pure rolling of a disc,a=฿r,where ฿is angular acceleration.a=ฯ/I×ra=f.r/0.5mr^2×ra=2f/m.buta=Fnet/m so a=f/m.which one is correct and why?I have attached a picture of my dpubt also.

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In case of pure rolling of a disc,a=฿r,where ฿is angular acceleration.a=ฯ/I×ra=f.r/0.5mr^2×ra=2f/m.buta=Fnet/m so a=f/m.which one is correct and why?I have attached a picture of my dpubt also.

In case of pure rolling of a disc,a=฿r,where ฿is angular acceleration.a=ฯ/I×ra=f.r/0.5mr^2×ra=2f/m.buta=Fnet/m so a=f/m.which one is correct and why?I have attached a picture of my dpubt also.

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