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In a new system of units energy, density and power are taken as fundamental units, then the dimensional formula of momentum will be ---------

Kanika , 6 Years ago
Grade 11
anser 2 Answers
Eshan

Last Activity: 6 Years ago

[Energy]=[ML^2T^{-2}]
[Density]=[ML^{-3}]
[Power]=[ML^2T^{-3}]

[Momentum]=[MLT^{-1}]=[Energy]^x[Density]^y[Power]^z

\implies x=\dfrac{7}{5}, y=\dfrac{1}{5}, z=\dfrac{-3}{5}

Khimraj

Last Activity: 6 Years ago

Energy E = [ML2T-2]
Density D = [ML-3]
Power P = [ML2T-3]
Momentum = [MLT-1] = ExDyPz
SO x = 7/5, y = 1/5, z = -3/5
Then 
Momentum = [E7/5D1/5P-3/5].
Hope it clears.

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