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In a gravity free space, a man of mass M standing at a height h above the floor, throws a ball of mass m straight down with velocity u. When the ball reaches the floor, the distance of the man above the floor will be??


4 years ago

DR STRANGE
212 Points
							HI ARIN, this is the concept of center of massinitially the center of mass of them is at height h above the floor, after he he throws the ball the center mass should remain stationary.let the distance of the man from th floor as ball reaches the floor be h+x (DISTANCE BETWEEN MAN AND THE BALL) the distance of center of mass from the ball at floor is h.mathematically, $M\times \frac{h+x}{M+m} = h$solve it for x, $x=\frac{hm}{M}$ distance of the man above the floor will be h+x (just add them)I hope you will get itplz approve if you are satisfied :)

4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions