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Grade: 11
        
If velocity of car decrease by 50% then % in stopping distance is ....
one year ago

Answers : (1)

Khimraj
3008 Points
							
let the velocity is u and retardation is a and stoppind distance s
then
 02 =  u2 – 2as
then s = u2/2a
If velocity of car decrease by 50%
then
u2/4 = u2 – 2ad
then d = 3u2/8a
so it is 75% of the stopping distance.
Hope it clears.
one year ago
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