Grade 10Mechanics

if three particles of masses 2kg,1kg and 3kg are placed at corners of an equilateral triangle of perimeter 6m then the distance of centre of mass which is at origin of particles from 1kg mass is

pawan

9 Years agoGrade 10

1 Answer

Vikas TU

9 Years ago

From the border of triangle, we can figure the side of triangle

 Side of triangle is 2m.

Settle An as your reference point. So your 1 kg mass is at A (0, 0), 2 kg mass is at B (0.5, 0.866) and the 3 kg mass is at C (1, 0)

By definition Center of Mass is the point where the entire mass of the framework gives off an impression of being concentrated and it is the weighted mean of directions alongside their masses

ie X (CM) = (m1x1+m2x2+m3x3...+mnxn)/(m1+m2+m3...+mn)

In like manner, Y (CM) is gotten by utilizing the Y organizes.

(X (CM), Y (CM)) gives you the directions of the focal point of mass.

For this situation

m1 = 1kg (x1, y1)=(0, 0)

m2 = 2kg (x2, y2)=(0.5, 0.866)

m3 = 3kg (x3, y3)=(1, 0)

Presently apply the equation

X (CM) =( (1*0)+(2*0.5)+(3*1))/(1+2+3) = 0.667.

Y (CM)= ((1*0)+(2*0.866)+(3*0))/(1+2+3) = 0.286

Presently, A (0, 0) CM (0.667, 0.286)

Utilize the separation between two focuses equation.. The appropriate response will be 0.7267 meters.

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if three particles of masses 2kg,1kg and 3kg are placed at corners of an equilateral triangle of perimeter 6m then the distance of centre of mass which is at origin of particles from 1kg mass is

pawan

1 Answer

Vikas TU

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