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Grade: 11
        
If the vertices of a quadrilateral is given by (x2 – 4)2 + (y2 – 9)2 = 0 then area of quadrilateral is-
(A) 36 (B) 24
(C) 16 (D) 81
2 years ago

Answers : (5)

downey zer
73 Points
							
here we see the sum of two squares is equal to zero
since both terms are positive and equal to 0
therefore both have to be equal to 0
therefore x=2,-2 and y=3,-3
area =24
2 years ago
hiphop aadhi2001
25 Points
							
Downey Zer 

         Please Can you explain the steps clearly....???
What comes after this step?  How did you got the answer
therefore x=2,-2 and y=3,-3
area =24

 
2 years ago
siddhi
24 Points
							you will get after solving A =2,3 B=2,-3 C=-2,3 D =-2,-3  Now u can use the determinant method to find the answer remember to take the vertices in order .Thank u
						
2 years ago
downey zer
73 Points
							sorry for
						
2 years ago
downey zer
73 Points
							
sorry for the delay. siddhi is right u can use the determinant method. OR what u can do is plot the points in the x-y plane and u will find that the points form a rectangle of length 4 units on one side and 6 units on other side. So i was able to tell the area to be 24 just by looking at the points. with enough practice u will also be able to find cool tricks to solve the problems easily. hope that helps.
2 years ago
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  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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