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`        If the vertices of a quadrilateral is given by (x2 – 4)2 + (y2 – 9)2 = 0 then area of quadrilateral is-(A) 36 (B) 24(C) 16 (D) 81`
2 years ago

downey zer
73 Points
```							here we see the sum of two squares is equal to zerosince both terms are positive and equal to 0therefore both have to be equal to 0therefore x=2,-2 and y=3,-3area =24
```
2 years ago
25 Points
```							Downey Zer          Please Can you explain the steps clearly....???What comes after this step?  How did you got the answertherefore x=2,-2 and y=3,-3area =24
```
2 years ago
siddhi
24 Points
```							you will get after solving A =2,3 B=2,-3 C=-2,3 D =-2,-3  Now u can use the determinant method to find the answer remember to take the vertices in order .Thank u
```
2 years ago
downey zer
73 Points
```							sorry for
```
2 years ago
downey zer
73 Points
```							sorry for the delay. siddhi is right u can use the determinant method. OR what u can do is plot the points in the x-y plane and u will find that the points form a rectangle of length 4 units on one side and 6 units on other side. So i was able to tell the area to be 24 just by looking at the points. with enough practice u will also be able to find cool tricks to solve the problems easily. hope that helps.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions