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Grade 12th passMechanics

if the twelve partucals are distributed randomly between 2 boxes A and B with equal probability , then the probabikity of the most probable distributioin will be ?

Profile image of kiran adhikari
9 Years agoGrade 12th pass
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To tackle the problem of distributing twelve particles randomly between two boxes, A and B, we first need to understand the concept of probability in this context. Each particle has an equal chance of being placed in either box, which means that for each particle, there are two possible outcomes: it can go into box A or box B. The question asks for the probability of the most probable distribution of these particles.

Understanding the Distribution

When distributing 12 particles between two boxes, we can denote the number of particles in box A as \( k \) and the number in box B as \( 12 - k \). The possible values for \( k \) range from 0 to 12. The probability of any specific distribution can be calculated using the binomial distribution formula:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

  • C(n, k) is the binomial coefficient, representing the number of ways to choose \( k \) successes (particles in box A) from \( n \) trials (total particles).
  • p is the probability of success (in this case, 0.5 for box A).
  • n is the total number of particles (12).

Calculating the Most Probable Distribution

The most probable distribution occurs when the number of particles in both boxes is as equal as possible. For 12 particles, the most balanced distributions are when:

  • Box A has 6 particles and Box B has 6 particles.

To find the probability of this distribution, we calculate:

P(X = 6) = C(12, 6) * (0.5)^6 * (0.5)^(12-6)

Calculating the binomial coefficient \( C(12, 6) \):

C(12, 6) = 12! / (6! * (12 - 6)!) = 924

Now, substituting this back into the probability formula:

P(X = 6) = 924 * (0.5)^{12} = 924 / 4096 ≈ 0.2256

Conclusion on the Most Probable Distribution

The probability of the most probable distribution, where 6 particles are in box A and 6 in box B, is approximately 0.2256, or 22.56%. This means that if you were to conduct this experiment many times, about 22.56% of the time, you would expect to find an equal distribution of particles between the two boxes.

In summary, the most probable distribution of 12 particles between two boxes A and B is when both boxes contain 6 particles each, with a probability of about 22.56% for this specific arrangement. This illustrates the beauty of probability and how it governs random distributions in a balanced manner.