If the pitcher's mound is 1.25 ft above the baseball field, can a pitcher release a fast ball horizontally at 92.0 mi/h and still get it into the strike zone over the plate 60.5 ft away? Assume that, for a strike, the ball must fall at least 1.30 ft but no more than 3.60 ft

Question

Jitender Pal · Answer

Therefore it takes 0.448 s for the ball to get at the strike plate.

The negative sign highlights the fact that the ball is going downwards.
Therefore the vertical displacement of the ball is 3.21 ft.
The vertical distance of the falling ball is well within range 1.30 ft and 3.60 ft, therefore the ball is in the strike zone.

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If the pitcher's mound is 1.25 ft above the baseball field, can a pitcher release a fast ball horizontally at 92.0 mi/h and still get it into the strike zone over the plate 60.5 ft away? Assume that, for a strike, the ball must fall at least 1.30 ft but no more than 3.60 ft

If the pitcher's mound is 1.25 ft above the baseball field, can a pitcher release a fast ball horizontally at 92.0 mi/h and still get it into the strike zone over the plate 60.5 ft away? Assume that, for a strike, the ball must fall at least 1.30 ft but no more than 3.60 ft

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