Grade 12th passMechanics
If the particle has a velocity of 5m/s along x-axis at origin, where it will be located at t=6s
1 Answer
Ritik
a=dv/dt
We know that a=2t+1
Which gives,
2t+1=dv/dt
Solve this differential equation.
∫0t(2t+1)dt=∫5vdv (limit LHS-0 to t, RHS-5 to v)
Which gives us the velocity as a function of time.
t^2+t=v−5.
Put t=6s to get the velocity at t=6sec
v=36+6+5
Finally, We get v=47m/s
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