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If the maximum velocity and accelaration of a particle executing SHM are equal in magnitude, the time period will be ?

If the maximum velocity and accelaration of a particle executing SHM are equal in magnitude, the time period will be ?

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear student
 
As 
w²A = wA
 
Hence w = 1
 
Now
 
As T = 2 pi/w = 2pi/1 = 2 pi = 6.28 sec
 
Regards
Arun (askIITians forum expert)

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