If the averagevelocity of a free falling body is numerically equal to half the acceleration due to gravity. Find the velocity of the body as it reaches the ground

A freely falling body has average velocityV(av.) = (1/2). numerical value of g in m/ssuppose it travelled for t secsso velocity of striking the ground v = u + g.t = g.tif it has travelled a distance h in t secondsh= (1/2) g.t^2but the same distance it must have travelled with average velocity V(av.)h = V(av.). t =(g/2).t = (1/2) g.t^2therefore t= 1 sso, v = g.1 m/sthe velocity with which it strikes the ground = g m/s