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If the angle of a projectile is 60 degree, then what is the height of it when the horizontal distance travelled is 3R/4 where R is the range of the projectile
If the angle of a projectile is 60 degree, then what is the height of it when the horizontal distance travelled is 3R/4 where R is the range of the projectile

```
3 years ago

Prashant Kumar
21 Points
```							Hlo frnds Use equation of trajectoryY= xtanθ(1-x/R)(x = horizontal did.)Substituting the value we get;H=3R/4 * tan60°(1-¾R/R)= 3√3R/4* (1-3/4)=3√3R/16Height = 3√3R/16
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions