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`        If t1andt2 are the times of flight for two complimentary angles then the range of projectile R is.???`
one year ago

```							complimentary angles :   two angles whose sum is 90°.RANGE OF PROJECTILE   =      ( u2 sin2x)/g            where x = angle so sin2x = 2sinxcosx if angles are complimentry ,say , a and 90-a sin2a = 2sinacosa sin2(90-a) = 2sin(90-a)cos(90-a) = 2cosasinaNow t1 and t2 be two time of flight As sin2x is same , u and g are constant so t1 = t2
```
one year ago
```							Dear student R = u² sin2A /g Now R = u² sin 2(90-A) /g R = u² sin 2A/g Same Range Hence of a particle is projected woth two complimentary angles, its range is same
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one year ago
```							it means the range is same for complementary angles range for t1 = range for t2.example : For complementary angles, the two possible sets could be -θ1 = 30 deg , θ2 = 60 deg; orθ1 = 60 deg , θ2 = 30 degFor all of the above angles of projection, sin 2θ comes out to be the same value
```
one year ago
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