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If resultant of two forces is 200N vertical, determine magnitude and direction of F2(refer figure no. 1 attached)
F2sin(theta)+F1sin(30)=200Or,F2sin(theta)+100sin(30)=200Or,F2sin(theta)+50=200Or,F2sin(theta)=150As the resultant has no horizontal component,soF2cos(theta)=F1cos30=(100×root3)/2=50root3.Divide the two equations.tan(theta)=150/(50root3)=3/root3=root3So theta=60.Use the equationF2sin(theta)=150Or,F2sin(60)=150Or,F2=300/root3=100root3.If it helps please approve.
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