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`        If g on the surface of the earth is 9.8m/s2. Find its value at depth of 3200km`
2 years ago

Arun
24739 Points
```							Dear,g=GM/r^2 , let the volume mass density of earth be =p,g=G4/3pi.r^3.1/r^2=G.4pi.r/3When radius is halved g`=G.2pi.r/3=g/2Hence, g=4.9m/s^2 at depth of 3200 km
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions