Grade 12Mechanics
If displacement of particle is x=sin(5pi t) +4cos(5pi t). Then amplitude is
3 Answers
Sandeep Bhamoo
Amplitude is the maximum value of displacement (here given by x). For maximum value of x , (dx)/dt = 0 On solving we get time at which x is max. it is tan(5πt)=4 on putting value of t , x = 8/(√17). Please do approve my answer if correct.
Khimraj
Maximum and minimum value of x is 
and -. So particle is oscillating between these positions. So amplitude will be given by
2A = - (-) = 2.
So A = .
Hope it clears.
2A = 4 - (-3) =
Khimraj
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