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if a stone is to hit a point which is at a distance d away and at a height h above the point from where the stone start then the value of initial speed U if the stone is Launched at an angle theta is
Dear student U = sqrt [g d2 / 2(d tan theta – h)cos2 theta] Hope it helps RegardsArun (askIITians forum expert)
When a projectile is protected at some angle from the certain height :- H=usin theta T-1/2gt^2 ----1 & t=x/ucos theta where x is distance d put value of t in 1 equation *H=usin theta ( d/ucos theta) -1/2g (d/ucos theta) ^2 H=d/cos theta √g/2(d tan theta-h)
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