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# If a person stands at the origin and throws three number of balls X,Y,Z with each having equal velocity ‘u’ making different angles with the horizontal.Then which ball spends much of it’s time in the air? Which ball would probably have maximum Range?    (Given: Angle made by Z is greater than y and Y greater than X).

Khimraj
3007 Points
3 years ago
time of flight
T = 2usin$\Theta$/g
As u for all is equal so ball having more angle will spends much of it’s time in air.
So correct answer is ball Z
Range
R = u2sin2$\Theta$/g
here if $\Theta$
ball having max angle will have max range
and if $\Theta$>45 for all three ball then
ball having min angle will have max range.
Hope it clears.