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`        If a particle moving with velocity −4 m/s i^ and acceleration is 2 m/s2i^. What is distance travelled by the paricle in 6 sec.`
8 months ago

Arun
13145 Points
```							Dear studenta = -2u = 4NowFrom v = u +a*t0 = 4 - 2tt = 2sec Hence after 2 sec it will stop as speed will be zero.NowWe have to find the distance covered in 2sec.S = u*t + (1/2) *a *t²S = 8 - (1/2)* 2 *2²S = 8 -4 = 4 m RegardsArun (askIITians forum expert)
```
8 months ago
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## COUPON CODE: SELF10

### Course Features

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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions