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Grade: 12
        If a particle moving with velocity −4 m/s i^ and acceleration is 2 m/s2i^. What is distance travelled by the paricle in 6 sec.
11 months ago

Answers : (1)

Arun
15797 Points
							
Dear student
a = -2
u = 4
Now
From v = u +a*t
0 = 4 - 2t
t = 2sec
 
Hence after 2 sec it will stop as speed will be zero.
Now
We have to find the distance covered in 2sec.
S = u*t + (1/2) *a *t²
S = 8 - (1/2)* 2 *2²
S = 8 -4 = 4 m
 
Regards
Arun (askIITians forum expert)
11 months ago
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