If a particle moving with velocity −4 m/s i^ and acceleration is 2 m/s2i^. What is distance travelled by the paricle in 6 sec.

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Arun · Answer

Dear student a = -2 u = 4 Now From v = u +a*t 0 = 4 - 2t t = 2sec Hence after 2 sec it will stop as speed will be zero. Now We have to find the distance covered in 2sec. S = u*t + (1/2) *a *t² S = 8 - (1/2)* 2 *2² S = 8 -4 = 4 m Regards Arun (askIITians forum expert)

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If a particle moving with velocity −4 m/s i^ and acceleration is 2 m/s2i^. What is distance travelled by the paricle in 6 sec.

If a particle moving with velocity −4 m/s i^ and acceleration is 2 m/s2i^. What is distance travelled by the paricle in 6 sec.

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If a particle moving with velocity −4 m/s i^ and acceleration is 2 m/s2i^. What is distance travelled by the paricle in 6 sec.

If a particle moving with velocity −4 m/s i^ and acceleration is 2 m/s2i^. What is distance travelled by the paricle in 6 sec.

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