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# If a cycle wheel of radius 4 m completes one revolution in two seconds, then acceleration of a point on the cycle wheel will be-(1)π^2m/s^2(2)2π^2m/s^2(3)4π^2m/s^2(4)8π^2m/s^2

4 years ago

## Answers : (1)

Vikas TU
14146 Points

angular velocity would be:
w = theta/time = 2*pi/2 = pi rad
accln. = w^R = > pi^2 * 4 = 4*pi^2 m/s^2.
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions