×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
If a boy can throw a stone of maximum height of 25m, he can throw the same stone to a distance of ?

```
3 years ago

## Answers : (1)

Arun
25211 Points
```							 Given vertical height = 25m. if we took it as max vertical heightthen, u2/2g = 25m => u2/g = 50 As horizontal projectile range = u2sin2∂/gSo, range is maximum when ∂=45 degrees Hence, maximum horizontal range is u2/g = 50,m
```
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions