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`         If a body of mass 3 kg is dropped downwards, after 1 sec another ball is dropped downwards from the same point. What is the distance between them after 3 sec.(a) 25 m                (b) 20 m(c) 50 m                (d) 9.8 m how do you solve this question?`
5 years ago

## Answers : (1)

Archita
132 Points
```							for the 1st balldistance moved in 3 seconds, s=ut+(1/2)gt2for a freely falling body u=0 s=(1/2)gt2s=(1/2)×10×32s=45m for the 2nd ballwhen real time = 3s the body has been let into free fall for only 2s as the 2nd ball was dropped one second after the first ballhence t=2s s=ut + (1/2)gt2s=(1/2)×10×22s=20m distance between them =                                              (45-20)m                                            =25m if u have any doubts ask in answer box.approve if helpful
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions