Grade 12th passMechanics
If a black body radiates 20 calories per second at 227°C, it will radiate at 727°C
If a black body radiates 20 calories per second at 227°C, it will radiate at 727°C
1 Answer
Arun
Energy emitted by a body is directly proportional to T^4 (Stefan's law)
so E1/E2 = (T1/T2)^4
x/20 = (727+273/227+273)^4 ..Absolute temp in Kelvin
x = 16*20 = 320 calories per second
so E1/E2 = (T1/T2)^4
x/20 = (727+273/227+273)^4 ..Absolute temp in Kelvin
x = 16*20 = 320 calories per second
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