If a ball of steel (density p=7.8g cm-3) attains a terminal velocity of 10cm s-1 when falling in water (Coefficient of viscosity ?water = 8.5*10-4 Pa.s), then, itsterminal velocity in glycerine (p=1.2g cm-3, ?=13.2 Pa.s) would be, nearly(a) 6.25 * 10-4 cm s-1(b) 6.45 *10-4 cm s-1(c) 1.5 * 10-5cm s-1(d) 1.6 * 10-5cm s-1
Simran Bhatia , 10 Years ago
Grade 11
1 Answers
Kevin Nash
Last Activity: 10 Years ago
(a)
Vpg = 6p?rv = Vplg
? Vg
(p -pl) = p?rv
Also
Vg (p - pl) = 6 p?’rv’
?
v’?’ = - (p - pl)/ (p - pl) * v?
? v’
= (p - pl)/ (p - pl) * v?/?’
=
(7.8 – 1.2)/(7.8 – 1) * 10 * 8.5 * 10-4/13.2
? v’
= 6.25 * 10-4 cm/s
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free