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`        If a ball is thrown from a height and it falls on the ground, how are we to calculate the time taken? The projectile part till that height can be calculated by 2usina/g but the rest of the motion, ie falling from that height to the ground how do we calculate that?`
2 years ago

53 Points
```							We can use energy conservation fro this purpose.Consider that the ball is initially thrown with velocity ‘u’ from a height ‘h’.It will have its final velocity ‘v’ just before hitting the ground.So we can use energy conservation for the situation-therefore      total initial energy = total final energy;(1/2mu2+mgh)=(1/2mv2)       where m= mass of the ball; u=initial velocity; v=final velocity before hitting the ground; h=height from where the ball is thrown; g= gravitational acclerationNOTE:- here we have taken ground as the reference.    If you agree with my answer please click “Approve” below.
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2 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions