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If a, b and c are the distances moved by a particle moving with a constant acceleration during the lth, mth and nth second of its motion respectively, show that a(m-n) + b(n-l) +c(l-m)=0

Aarush , 8 Years ago
Grade 11
anser 1 Answers
gavini haritha
This is related to coordinate geometry so let us assume that a=1,b=2,c=3 is the distance traveled by the body at1s,2s,3s . Then by substituting we get 1(2-3)+2(3-1)+3(1-2)=0
Last Activity: 8 Years ago
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