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If a 2 kg bomb explodes at the top most point and breaks into 2 part each of 1 kg if 1 part retraces it's path to the point of projection find out distance of 2 part from point of projection given angle of projection is 45 degree If a 2 kg bomb explodes at the top most point and breaks into 2 part each of 1 kg if 1 part retraces it's path to the point of projection find out distance of 2 part from point of projection given angle of projection is 45 degree
Let range of projectile be Rthen as there is no horizontal force on the body the com will not have any path other than the projectile Therefore if the body does not break it should reach at rTherefore when the body breaks it's com should be at rAt final position fragment be at X ( from point of projection )X=2r by conserving the position of com
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