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Grade 11Mechanics

I`ve attached the question as an image...It is somewhat typical...Please give me a clear solution

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Profile image of P Nikhil Sai Chandra
10 Years agoGrade 11
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1 Answer

Profile image of Mallikarjun Maram
10 Years ago
When the coin is about to slip, centripetal force is just equal to the limiting friction.  m\omega ^{2}r = \mu mg.  Substitute the values and solve for \omega, you will get the answer 84.54 rpm after proper unit conversion.