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i have attached the question along with image.pls give me the answer.it was previous iit question

revanth , 9 Years ago
Grade 11
anser 1 Answers
Sahil khan

Last Activity: 9 Years ago

at time t=0,
p1=m1v1+m2v2.
at time t=2t,
p2=m1v’1+m2v’2.
now, rate of change of linear momentum is (p1-p2)/2t,
F=dp/dt=m1g+m2g     (rate of chnage of momentum is equal to force acting on particles),
m1v’1-m1v’2=(m1+m2)g2t.
option ©.
 

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