Grade 11Mechanics
how to find velocity at half of maximum height provided velocity is v and range is max
1 Answer
Vikas TU
Maximum Height = v^2/2g
Half of Max. Height = H/2 =>H’ = v^2/4g
Range is maximum means thetha of projection = 45 degree.
Therfore at half of max. height = > H = u^2/8g
u^2 = 8gH
u = root(8gH) m/s
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