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how to find velocity at half of maximum height provided velocity is v and range is max

vishwajeet , 7 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Maximum Height = v^2/2g
Half of Max. Height = H/2 =>H’ = v^2/4g
Range is maximum means thetha of projection = 45 degree.
Therfore at half of max. height = > H = u^2/8g
u^2 = 8gH
u = root(8gH) m/s

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