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How to do this.Please help me to answer since my jee exams are near please

Aiswarya , 6 Years ago

Grade 10

1 Answers

Eshan

Last Activity: 6 Years ago

Let the speed of the wedge at that time be $v'$ .

From conservation of linear momentum,

$Mv'=mv$
$\implies v'=\dfrac{mv}{M}$

From conservation of energy,

$mgh=\dfrac{1}{2}mv^2+\dfrac{1}{2}Mv'^2 =\dfrac{1}{2}mv^2(1+\dfrac{m}{M})$

From work energy theorem applied on the block,

Work done by gravity+Work done by normal force=Gain in kinetic energy of the block

$\implies mgh+W_N=\dfrac{1}{2}mv^2$
$\implies W_N=-\dfrac{1}{2}\dfrac{m^2}{M}v^2$

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