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Grade: upto college level
        
How much work is done by pressure in forcing 1.4 m3 of water through a 13-mm internal diameter pipe if the difference in pressure at the two ends of the pipe is 1.2 atm?
4 years ago

Answers : (2)

Navjyot Kalra
askIITians Faculty
654 Points
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232-227_1.PNG
4 years ago
H
13 Points
							
Actually, since density= m/V once substituted, the equation should be(p_{1} - p_{2}) V = 1/2 \rho (v_{1}^{2} - v_{2}^{2}) therefore, Work would be\frac{(1.2 atm)(\frac{1.01\ast 10^5 pa}{1 atm})}{1.4 m^3}(1.2 atm) \frac{(1.01\ast 10^5 pa)}{1 atm} (1.4 m^3 ) which gives a final answer of 1.697 \ast 10^5 J
 
 
 
 
6 months ago
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