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How much power, in horsepower, must be developed by the engine of a 1600-kg car moving at 26 m/s ( = 94 km/h) on a level road if the forces of resistance total 720 N?
How much power, in horsepower, must be developed by the engine of a 1600-kg car moving at 26 m/s ( = 94 km/h) on a level road if the forces of resistance total 720 N?

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5 years ago

Deepak Patra
471 Points
```							We have to find out the power developed by the engine of a 1600-kg car moving at 26 m/s (= 94 km/h) on a level road if the forces of resistance total 720 N.To obtain power (P), substitute 720 N for F and 26 m/s for v in the equation P = Fv,P = Fv = (720 N) (26 m/s) = 18720 N. m/s= (18720 N. m/s) (1 W/1 N.m/s)= 18720 W= (18720 W) ((1/745.7 hp) / W)= 25.10 hp …… (2)Rounding off to two significant figures, the power which is developed by the engine will be 25 hp.
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5 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions