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How is the time period of a spring mass system = 2 pi (disp/accn)1/2 ?

Chirag Jain , 8 Years ago
Grade 12
anser 1 Answers
arun

Last Activity: 8 Years ago

standard equation of S.H.M is 
\frac{\partial^2 x}{\partial t^2} + \omega ^2 x =0
a = -\omega ^2 x
\left | a\div x \right |= \omega ^2
2\pi \div T=\omega
T = 2\pi \div \omega
T = 2\pi \div \sqrt{\omega ^2}
T = 2\pi \div \sqrt{a\div x}
T = 2\pi \sqrt{x\div a}
this means time period of of S.H.M is square root of displacement divided by acceleration.
 

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