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How fast must an 816-kg Volkswagen travel to have the same momentum as (a) a 2650-kg Cadillac going 16.0 km/h? (b) a 9080-kg truck also going 16.0 km/hr?

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5 years ago

```							a)52 kmph approx. b)178kmphM1V1=M2V2
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5 years ago 396 Points
```							(a) Mass of Volkswagen, m = 816-kgMass of Cadillac, m1 = 2650-kgVelocity of Cadillac, v1 = 16.0 km/hLet us consider velocity of the Volkswagen is v.Momentum of a particle (p) is equal to the mass of the particle (m) times velocity of the particle (v).So the momentum of Volkswagen (p) will be,p = mv = (816-kg) v …… (1)andthe momentum of Cadillac (p1) will be,p1 = m1 v1 = (2650-kg) (16.0 km/h) = 42400 kg. km/h …… (2)Since the momentum of the Volkswagen and Cadillac is same, therefore,p = p1(816-kg) v = 42400 kg. km/hSo, v = (42400 kg. km/h)/ 816-kg = 51.96 km/h …… (3)Rounding off to three significant figures the velocity of the Cadillac will be 52.0 km/h.(b) Mass of Volkswagen, m = 816-kgMass of truck, m2 = 9080-kgVelocity of truck, v2 = 16.0 km/hLet us consider velocity of the Volkswagen is v.Momentum of a particle (p) is equal to the mass of the particle (m) times velocity of the particle (v).So the momentum of Volkswagen (p) will be,p = mv = (816-kg) v …… (4)andthe momentum of truck (p2) will be,p2 = m2 v2 = (9080-kg) (16.0 km/h) = 145280 kg. km/h …… (5)Since the momentum of the Volkswagen and truck is same, therefore,p = p2(816-kg) v = 145280 kg. km/hSo, v = (145280 kg. km/h)/ 816-kg = 178.04 km/h …… (6)Rounding off to three significant figures the velocity of the truck will be 178.04 km/h.
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5 years ago
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