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How does Young`s modulus change with rise in temperature? A load of 2kg produces an extension of 1mm in wire of 3mm in length and 1mm in diameter. Calculate the Young`s modulus of elasticity of the wire?
stress = Force /Area of contact => 20/(pi*0.5*0.5) N/mm^2strain = delta(l)/l = > 1/3Young’s mudulus = stress/strainHence,Y = 20*3/(pi*0.5*0.5) = > 76.43312 N/mm^2
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