Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        How do you solve this question? The answer is B......................................`
one year ago

Arun
24496 Points
```							H = u² sin²A /2g .................. (1)R=u^2 sin2A /g .........................(2)If the projectile just has to pass the point (30,40)m then it must be the peak point of the motion.There fore put H= 40 and R = 2 x 30then divide H by R and obtain tanA as 8/3then calculate sin^2 A from tanA and put in eq. 1 to obtain u as 30m/sso ans is b, 30 m/s
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions