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Grade: 11
        
How do you solve this question? The answer is B......................................
6 months ago

Answers : (1)

Arun
21037 Points
							
H = u² sin²A /2g .................. (1)
R=u^2 sin2A /g .........................(2)

If the projectile just has to pass the point (30,40)m then it must be the peak point of the motion.

There fore put H= 40 and R = 2 x 30

then divide H by R and obtain tanA as 8/3
then calculate sin^2 A from tanA and put in eq. 1 to obtain u as 30m/s
so ans is b, 30 m/s
6 months ago
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